Monday, February 13, 2017

CIVIL ENGINEER: 1cum cement = how much bag?





Assumptions:

1.Nominal mix is 1:2:4
2.Wastage of cement during handling is considered as :2%.
3.Output from mixer is considered as 67% in volume of the input.
( For getting 1 Cum output , we need dry mix as 1/0.67= 1.49 say 1.50 Cum).
4.Density of cement : 1440 Kg/cum.
   Mass of one bag   = 50kg
   Volume of one bag of cement = 50/1400 =0.035714 m3
    No. of bags in m3                  =1/0.035714 =28 bags

With these assumptions about data , the actual calculations are as follows :
Cement per CuM = 1.52 *28.8 /( 1+2+4 )
= 1.52*28.8/7 = 6.25 Bags

Same formula can be used for calculating cement for other nominal mixes also.
In case you feel that cement is wasted more than 2 % , proceed as under :
Wastage : 5 %
Take the factor of 1.5 +0.05 = 1.55 instead of 1.52 in the above formula.